The equation {sin ^2}theta = frac{ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Now, $\sin ^{2} 	heta=\frac{x^{2}+y^{2}}{2 x y}$

$	herefore \mathrm{x},$ $y$ have same sign

$\frac{x^{2}+y^{2}}{2 x y}=\frac{1}{2}\left[(\sqrt

Vedclass · Accepted Answer

$x = y$

Vedclass · Answer

Now, $\sin ^{2} 	heta=\frac{x^{2}+y^{2}}{2 x y}$

$	herefore \mathrm{x},$ $y$ have same sign

$\frac{x^{2}+y^{2}}{2 x y}=\frac{1}{2}\left[(\sqrt{\frac{x}{y}}-\sqrt{\frac{y}{x}})^{2}+2ight] \geq 1$

Now, $\sin ^{2} 	heta \leq 1 .$

Therefore, $\frac{x^{2}+y^{2}}{2 x y}=1$

$  \Rightarrow x=y$

The equation ${\sin ^2}\theta = \frac{{{x^2} + {y^2}}}{{2xy}},x,y, \ne 0$ is possible if

Similar Questions

Find the value of the trigonometric function $\cot \left(-\frac{15 \pi}{4}\right)$

If $A = 130^\circ $ and $x = \sin A + \cos A,$ then

Find the value of the trigonometric function $\tan \frac{19 \pi}{3}$.

Find the degree measure of the angle subtended at the centre of a circle of radius $100 \,cm$ by an arc of length $22\, cm$ ( Use $\pi=\frac{22}{7}$ ).

Find the value of:

$\sin 75^{\circ}$